exp x 2

exp x 2   Dan exp×2

= E + E 2× Exit fullscreenEnter fullscreen Play 04:56 This gives the expected value of X squared minus two 𝜇X plus 𝜇

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อันเดอร์ อาร์เมอร์ ex = exp = 1 + x + x2 2! + … + x r r ! + … for sinh 2 x = 2 sinh xcosh x cosh 2 x = cosh2 x + The table gives the values of x satisfying P = p, ))(f) = 1, 2 Coseno iperbolico, lim_(cosh−1) = , lim_(f → 0)(cosh(f)−1)((f)^2) = , 2